1966 United States Senate election in Montana explained

Election Name:1966 United States Senate election in Montana
Country:Montana
Flag Year:1905
Type:presidential
Ongoing:no
Previous Election:1960 United States Senate election in Montana
Previous Year:1960
Next Election:1972 United States Senate election in Montana
Next Year:1972
Election Date:November 8, 1966
Image1:File:Lee Warren METCALF.jpg
Nominee1:Lee Metcalf
Party1:Democratic Party (United States)
Popular Vote1:138,166
Percentage1:53.17%
Nominee2:Tim Babcock
Party2:Republican Party (United States)
Popular Vote2:121,697
Percentage2:46.83%
U.S. Senator
Before Election:Lee Metcalf
Before Party:Democratic Party (United States)
After Election:Lee Metcalf
After Party:Democratic Party (United States)

The 1966 United States Senate election in Montana took place on November 8, 1966. Incumbent United States Senator Lee Metcalf, who was first elected to the Senate in 1960, ran for re-election. He won the Democratic primary uncontested, and moved on to the general election, where he was opposed by Tim M. Babcock, the Republican nominee and the Governor of Montana. Though the race remained close, Metcalf was able to expand on his 1960 margin of victory, and defeated Babcock to win a second term.

Democratic primary

Candidates

Results

Republican primary

Candidates

Results

General election

Results

See also